The width of a rectangle is 7 meters greater than its length

Step-by-step explanation:

The quadratic equation in standard form for the equation that would represent the area of the rectangle is x^2 + 7c - 170 = 0. The area (A) of the rectangle with length, x, and width, y, is: A = x * y. The width of a rectangle is 7 meters greater than its length: y = 7 + l. The area of the rectangle is 170 square meters: A = 170. Substitute A and y in the formula A = x * y. 170 = x * (7 + x). 170 = 7x + x^2. The standard form of the quadratic equation is ax^2 + bx + c = 0. Therefore, 170 = 7x + x^2 in the standard form is: x^2 + 7c - 170 = 0.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !