Simplify.
remove all perfect squares from inside the square root.

square root 112a^6

The simplified form of the expression is

Given the indices, , we need to remove all the perfect squares from the square root. This is as shown below:

Applying the law of indices, the expression will become:

Hence the simplified form of the expression is

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4√7*a^3

Step-by-step explanation:

a^6 is the same as (a^3)^2.  If we take the square root of this latter expression, the result will be a^3.

112 can be factored as follows:  2 * 56

                                                     2 * 7 * 8

                                                     2 * 7 * 2 * 4, or 7 4^2

Taking the square root of this last result yields 4√7.

Thus, √ (112a^6) = 4√7*a^3

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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answer:

step-by-step explanation: