In △abc the points m and n belong to the sides
ac and ab respectively. am/mc = an/nb = 2/3 .
prove that mn∥bc. find mn, if bc=20.

Try this solution, it consists of two parts (MN=8).

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier