In a study by the texas a & m university, found there were 23,000 prairie dogs in texas in 2000. by 2010, the number has increased to 40,000. the exponential growth function d=2.3e^kt describes the prairie dog population, d in ten thousands, t years after 2000.
a) solve for k
b)by this model how many prairie dogs existed last year?
c)in which year will the population double?
!

let x=k

D=dog

T=Taxes

I=increase P=population

solve k

d=23,000

t=2000

d=2.3e^

divide both sides by 2

after year is,2000+k2-2.3

=1.999.7

k2- 23,000=

k-x

or

k2-2

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.