What is the 6th term in the sequence described by the following recursive formula?

a1=9
an=an−1−4

a) a6=−7
b) a6=−15
c) a6=−8
d) a6=−11

Correct answer is: D) a₆ = - 11

Step-by-step explanation:

Given:

a₁ = 9 and aₙ = aₙ₋₁ - 4

We know it is

a₆ = a₅ + d also it is given a₆ = a₅ - 4

When we equate the right sides of equality we get:

a₅ + d = a₅ - 4 => d = - 4

We also know it is   a₆ = a₁ + 5 d

Now we will find a₆

a₆ = 9 + 5 (-4) = 9 - 20 = - 11

a₆ = - 11

God with you!!!

89

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.