X^2-8x+ _ =-1+_?

what do you have to add in order to complete the square

Hello from MrBillDoesMath!

_ =  (-4) ^2      (Which equals 16)

Discussion:

Generally

(x + a) ^ 2 = x^2 + 2ax + a^2

Note that the constant term in this perfect square equals the square of (1/2) the coefficient of x. Applying the fact to your equation, gives

x^2 - 8x + _ = -1 + _                    => -8/2  =  -4

x^2 - 8x + (-4)^2 = -1 + (-4)^2   =>

(x -4)^2             = - 1 + 16 = 15    =>

(x-4)^2 = 15                                 =>

x-4 = +\- sqrt(15)                        =>

x = 4 +\- sqrt(15)

Thank you,

MrB

i believe the answer is d.

hope it you! : d

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.