Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of ?

y + 2 =(x + 3)
y – 2 = (x – 3)
y + 3 = (x + 2)
y – 3 = (x – 2)

y – 2 = (x – 3)

Step-by-step explanation:

because (3, 2) was the point used for the equation but turned negative because you need to make it negative for the equation. y - y1 =m(x - x1)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: