Which of the following equations only have one solution? x2+4x+4=0, x2+x=0, x2-1=0

x2+4x+4=0

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminant. The discriminant is the inside portion of the square root from the quadratic formula.

• yields 2 real roots

• yields 1 real root

•[tx]b^2-4ac<0[/tex] yields no real roots

x2+4x+4=0 has a = 1, b = 4 and c = 4. So 4^2 - 4(1)(4) is 16 - 16 = 0. This yields 1 root.

x2+x=0 has a = 1 and b = 1 and c = 0. So 1^2 - 4(1)(0) = 1- 0 = 1. This yields 2 roots.

x2-1=0 has a = 1 and b = 0 and c= -1. So 0^2 -4(1)(-1) = 0 + 4 = 4. This yields 2 roots.

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: