Asupermarket chain sells oranges, apples, peaches, and bananas in three stores located throughout a large metropolitan area. the average number of pounds sold per day in each store is summarized in matrix m. “in season” and “out of season” prices, per pound, of each fruit are given in matrix n. what is the total, for the three stores, of “in season” daily revenue for the four fruits? the “out of season” peach sales represent what percentage of the daily total “out of season” revenues for store 3?

1877

64%

Step-by-step explanation:

         35 50 30 45     Store 1

         25 30 40 40     Store 2

         70 50 60 55     Store 3

              $3.30             $2.00

              $1.50            $5.70

              $4.20            $4.55

              $5.05            $4.00

35* 3.30 + 50* 1.50 + 30* 4.20 + 45* 5.05 (store 1)

= 543.75

25* 3.30 + 30* 1.50 + 40* 4.20 + 40* 5.05 (store 2)

= 497.5

70* 3.30 + 50* 1.50 + 60* 4.20 + 55* 5.05 (store 3)

= 835.75

543.75 + 497.5 + 835.75 = 1877

Total “out of season” revenues for store 3

= 70* 2.00 + 50* 5.70 + 60* 4.55 + 55* 4.00

= 918

Total peaches sale in "out of season"

= 30(4.55) + 40(4.55) + 60(4.55)

= 591.5

Percentage = 591.5/918 * 100%

                    = 64%

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: