(i will give 30 points)
for the function f(x) = (8-­2x)2 ,find f-­1 . determine whether f­-1 is a function.

answer choices:
f­-1(x) = ±8+x2−−−√; f­-1 is a function

f­-1(x) = ±8+x2−−−√; f­-1 is not a function

f­-1(x) = 8±x√2; f­-1 is not a function

f­-1(x) = 8±x√2; f­-1 is a function

4 ± 1/2sqrt(x) = y

This is not a function

Step-by-step explanation:

f(x) = (8-2x)^2

y = (8-2x)^2

To find the inverse function, exchange x and y and then solve for y

x = (8-2y)^2

Take the square root of each side

±sqrt(x) = 8-2y

Subtract 8 from each side

-8±sqrt(x) = 8-8-2y

-8±sqrt(x) = -2y

Divide by -2

-8/-2±  1/2sqrt(x) = -2/-2y

4 ± 1/2sqrt(x) = y

This is not a function

55? i think maybe

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)