What is an equation of the line that passes through the point (6, -1) and is parallel to the line 2x-3y=12

y = -(2/3)x - 5

Step-by-step explanation:

First we need to find the slope of the line 2x - 3y = 12 by solving for y...

2x - 3y = 12

         -3y = -2x + 12

              y = (2/3)x - 4

Parallel lines have the same slope, so the new line has a slope of (2/3), the equation for a line is y = mx + b, so we have m, and a point (x, y) of (6, -1), so plug in all the values and solve for b...

-1 = (2/3)(6) + b

     -1 = 4 + b

             -5 = b

So the line parallel is y = (2/3)x - 5

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

the 4th choice is the correct one

step-by-step explanation: