If c is a positive integer, how does the graph of y=x+c compare to the graph of y=x?

It is shifted c units to the left  .

Step-by-step explanation:

In general, adding a constant c to the value of x shifts a graph c units to the left.

The graph of y = x + c is parallel to y = x,  the y-intercept becomes (0, c) and the x-intercept becomes (-c, 0).

In the diagram below, the red line is the graph of y = x, and the blue line is the graph of y = x + 1.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

step-by-step explanation: