Ajawbreaker candy machine has 30 red jawbreakers, 40 green jawbreakers, 15 yellow jawbreakers, and 15 blue jawbreakers. if loretta puts 1 coin in the machine and gets 1 jawbreaker, what is the probability the jawbreaker is not green? pick the simplified version of the correct answer.

3/5 probability

Step-by-step explanation:

30 red + 40 green + 15 yellow + 15 blue = the total number of jawbreakers

the total number of jawbreakers = 100 jawbreakers

30 red + 15 yellow + 15 blue = the total number of jawbreakers that aren't green

or

100 jawbreakers - 40 green jawbreakers = the total number of jawbreakers that aren't green

the total number of jawbreakers that aren't green = 60 jawbreakers

60/100 = probability that the jawbreaker isn't green

or

6/10

or

3/5

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

l.ln.lln.k.nkl

step-by-step explanation: