Mathematics, 31.01.2020 03:59 ljwatts25

Aproportional relationship is shown in the table below:
xxx 000 111 222 333 444
yyy 000 333 666 999 121212
what is the slope of the line that represents this relationship?
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graph the line that represents this relationship.

Answers: 1

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Answer from: weeblordd

The slope is m=3

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

A(1,3) ------> from the given table

Find the value of k

k=y/x

substitute the values

k=3/1=3

The linear equation is

y=3x

using a graphing tool

see the attached figure

Aproportional relationship is shown in the table below: xxx 000 111 222 333 444 yyy 000 333 666 999

Answer from: shanice13

The slope of a proportional relationship is the rate of change of the relationship

The slope of the relationship is 3

Pick any two points from the table;

$\mathbf{(x,y) = (0,0) (1,3)}$

The slope (m) is calculated as:

$\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}$

So, we have:

$\mathbf{m = \frac{3 - 0}{1 - 0}}$

Subtract

$\mathbf{m = \frac{3}{1}}$

Divide

$\mathbf{m = 3}$

Hence, the slope of the relationship is 3

Because it is a proportional relationship, the equation of its graph is:

$\mathbf{y = mx}$

Substitute 3 for m

$\mathbf{y = 3x}$

See attachment for the graph of $\mathbf{y = 3x}$

Read more about proportional relationships at:

link

Answer from: Quest

Its equal to d=7.07in

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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Aproportional relationship is shown in the table below:
xxx 000 111 222 333 444
yyy 000...

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