Arocket launched vertically from the ground with an initial veocity of 56ft? sec (a) write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.
(b)graph h(t) on the coordinate plane.
(c) use your graph from part 3(b) to determine the rocket’s maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air.

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Step-by-step explanation:

Ballistic motion is usually modeled by the quadratic ...

  h(t) = -1/2g·t^2 +v0·t +h0

where g is the acceleration due to gravity, v0 is the initial upward velocity, and h0 is the initial height. Here, we have g = 32 ft/s^2, v0 = 56 ft/s, h0 = 0.

(A) That makes our quadratic function be ...

  h(t) = -16t^2 +56t

(B) see the attachment for a graph

(C) see the attachment for the time and height at the highest point.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

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step-by-step explanation: