Arecent survey concluded that the proportion of american teenagers who have a cell phone is 0.27. the true population proportion of american teenagers who have a cell phone is 0.29. for samples of size 1,000 that are selected at random from this population, what are the mean and standard deviation, respectively, for the sampling distribution of the sample proportion of american teenagers who have a cell phone?

The mean and standard deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone are:

Recall:

Given that:

Population proportion, p, is 0.29

Therefore,

Standard Deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone =  

p = 0.29

n = 1,000

Therefore, the mean and standard deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone are:

Learn more here:

link

The mean for the sampling distribution of the sample proportion is 0.29

The standard deviation for the sampling distribution of the sample proportion is 0.01435

Step-by-step explanation:

The mean for the sampling distribution of the sample proportion is always equal to the true population proportion, in this case; p = 0.29

The standard deviation for the sampling distribution of the sample proportion is calculated as;

Using the given values;

p = 0.29

1 - p = 0.71

n = 1000

The standard deviation becomes;

The s.d becomes 0.01435

5104.38 inches

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584