The measure of angle pqr is 75°. the length of radius qr is 8 inches. what is the approximate area of sector pqr? use 3.14 for pi .

  about 41.9 square inches

Step-by-step explanation:

The area of a sector of radius r and central angle α is given by ...

  A = (1/2)r^2·α

where α is in radians.

The angle 75° is equivalent to 75°·(π/180°) = 5π/12 radians, so the area is ...

  A = (1/2)(8 in)^2·(5/12)·3.14 = (40/3)·3.14 in^2 = 41.86_6 in^2 ≈ 41.9 in^2

Comment on the precision of the answer

The use of a 3-significant-digit value for pi means that the answer must be rounded to 3 significant digits. If the 8-inch value for radius is really only accurate to ±1/2 inch, then the answer must be rounded to 1 significant digit: 40 in^2.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}