In science class, jada uses a graduated cylinder with water in it to measure the volume of some marbles. after dropping in 4 marbles so they are all under water, the water in the cylinder is at a height of 10 milliliters. after dropping in 6 marbles so they are all under water, the water in the cylinder is at a height of 11 milliliters.
if this can be represented by a liner model, predict the height of the cylinder after dropping in 8 marbles.

The height of water in the cylinder after drooping 8 marbles is 12 mm

Step-by-step explanation:

∵ The change of the height of the water varies directly with the change of the  number of marbles

∵ (h2 - h1) α (x2 - x1)

∴ (h2 - h1) = k (x2 - x1)

∴ (11 - 10) = k (6 - 4)

∴ 1 = 2 k

∴ k = 1/2

∴ (h2 - h1) = 1/2 (x2 - x1)

∴ (Δh) = 1/2 (Δx)

∴ h3 - 11 = 1/2 (8 - 6)

∴ h3 = 1/2 × 2 + 11 = 12 milliliter

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

it would be a on edgenuit y

the diagram below is your final answer