Brainlies
suppose a spherical asteroid has a radius of approcimately 3.2x10^3 m. use the formula 4/3*pie* r^3 to find the approcimate volume of the asteroid

1.37 x 10^11
4.02 x 10^4
1.35 x 10^12
2.4 x 10^12

Option A which is 1.37 x 10^11

Step-by-step explanation:

Given that spherical asteroid's radius = 3.2 x 10^3

Formula to calculate volume of spherical asteroid

To find,

the approximate volume of spherical asteroid

4/3 π r^3

= 4/3 π (3.2 x 10^3)^3

=  4/3 π(32.786 x 10^9)

= ( 43.691 x 10^9 ) π

= 1.37258277 x 10^11

≈ 1.37 x 10^11

Thus, the approximate volume of spherical asteroid is 1.37 x 10^11

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6