![\large\boxed{72+28\sqrt[3]3}](/tpl/images/0393/2475/6f7cb.png)
![4\sqrt[3]3(7+6\sqrt[3]9)\qquad\text{use distributive property}\ a(b+c)=ab+ac\\\\=(4\sqrt[3]3)(7)+(4\sqrt[3]3)(6\sqrt[3]9)\qquad\text{use}\ \sqrt[3]{a}\cdot\sqrt[3]{b}=\sqrt[3]{ab}\\\\=(4\cdot7)(\sqrt[3]3)+(4\cdot6)(\sqrt[3]{(3)(9)})\\\\=28\sqrt[3]3+24\sqrt[3]{27}\qquad\sqrt[3]{27}=3\ \text{because}\ 3^3=27\\\\=28\sqrt[3]3+24(3)\\\\=28\sqrt[3]3+72](/tpl/images/0393/2475/6bcb6.png)
20 points
i need with the steps on this problem
4 3^squareroot 3 (7+6 3^s...
Mathematics, 27.11.2019 14:31 cvrechek
20 points
i need with the steps on this problem
4 3^squareroot 3 (7+6 3^squareroot 9)
i have the answer but need with steps
a: 72+28 3^squareroot 3
Answers: 1
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