Find the zeros of the polynomial function (show all work) f(x)=x^3 x^2-4x-4
( answer asap)

The zeros are -2, -1 and 2.

Step-by-step explanation:

I will assume that it is:

x^3 + x^2 - 4x - 4 = 0

Looks like x = -1  might be a root:

(-1)^3 + (-1)^2 - 4(-1) - 4

= - 1 + 1 + 4 - 4 = 0

So x = -1 is one zero.

As x = -1 is a zero then (x + 1) must be a factor of the expression so we divide:-

x + 1 ( x^3 + x^2 - 4x - 4  ( x^2 - 4  <  The quotient

         x^3 + x^2

                         -4x - 4

                          -4x - 4

So we have (x + 1)(x^2 - 4) = 0

(x + 1)(x - 2)(x + 2) = 0

Therefore  the zeroes are  -1,2 and -2,

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

the answer is 1/4

step-by-step explanation: