Sum of an infinite geometric series with a common ratio of -1

Hello from MrBillDoesMath!

a/2

Discussion:

The question is a bit unclear but i think they are asking for the

    sum (n = 1 to infinity) of   a*r^n

where "a" is the first term of the series and "r" is the common  ratio. Whne f = -1 the sum is

a/(1-r) = a/(1-(-1)) = a/(2)

Thank you,

MrB

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

bn,mn,n.vn.

step-by-step explanation: