a student needs 3 pieces of wire for a science project. the second piece must be 3 times as long as the first. the third piece must be twice as long as the second. the student has 350 inches of wire to make the three pieces. let x be the length of the first wire.
a. write an inequality that models this situation.
b. what are the possible lengths of the shortest piece of wire?
(this is solving inequalities using multiplication or division)

Part a) The inequality that represent the situation is

Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to

Step-by-step explanation:

Let

x------> the length of the first wire

3x---> the length of the second wire

2(3x)=6x -----> the length of the third wire

Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION

we know that

The inequality that represent the situation is

Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?

we know that

The shortest piece of wire is the first wire

so

Solve the inequality

Divide by 10 both sides

The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!

i think u have 12 apples sorry again i don't really know if it correct i'm just tryna hrlp people out.