2x+2y+3z=0
−2x−y+z=−3
Mathematics, 24.01.2020 14:31 jstephanie644
Solve the system by elimination. ( explain how to do it)
2x+2y+3z=0
−2x−y+z=−3
2x+3y+3z=5
Answers: 1
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You know the right answer?
Solve the system by elimination. ( explain how to do it)
2x+2y+3z=0
−2x−y+z=−3
2x+2y+3z=0
−2x−y+z=−3
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