Aly wants to use ready-made 8-foot long fence sections for her yard. the yard measures 24 feet long and 40 feet wide. the area of the first level of her house is 640 squared feet. how many fence sections would she need to enclose her entire years?

16

Step-by-step explanation:

To find out how many sections she needs, you need to find the perimeter

24 * 2 = 48

40 * 2 = 80

48 + 80 =128

If each section of fence is 8 feet then you divide 128 by 8 and get 16

If I did the math correctly, then the answer is 11.

Step-by-step explanation: 1 40 foot long piece and 2 24 ft. long pieces.

24 times 2 is 48 plus 40 is 88.

The width of her house, based on the question, is also 40 ft. so you could add 40 onto it, but I actually believe the answer is 11, because it's 88 feet. The fence piece is 8 ft. long, so divide 88 by 8 and you get 11.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

26

step-by-step explanation: