What is the sum of the first eight terms of a geometric series who’s first term is 3 and who’s common ratio is 1/2?

765/128 or 5.97

Step-by-step explanation:

You know that:

- The first term of the geometric serie is 3.

- The common ratio is 1/2 (r=1/2).

Therefore, you can apply the following formula:

Where is the first term, n i the number of terms and r is the common ratioo.

Substitute values and you obtain:

The sum of 8 terms = 5.98

Step-by-step explanation:

Formula:-

Sum of n terms of GP = a(1-rⁿ)/(1-r)

a - first term

r common ratio

It is given that,

In a GP first term is 3 and who’s common ratio is 1/2

To find the sum of 8 terms

Sum of n terms of GP = a(1-rⁿ)/(1-r)

a = 3 , r = 1/2 and n = 8

sum = 3(1 - (1/2)⁸)/(1 - 1/2)

= 3(1 - (1/2)⁸)/(1/2)

= 6(1 - 0.0039) = 5.98

Therefore sum of 8 terms = 5.98

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

a

step-by-step explanation:

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