At the movie theater, child admission is $5.20 and adult admission is $8.60. on friday, 132 tickets were sold for a total sales of $931.20. how many tickets of each category were sold that day?

60 child tickets and 72 adult tickets

Step-by-step explanation:

Let x denote the number of child tickets sold and y the number of adult tickets sold. The problem involves solving the following system of linear equations; x+y=132 and 5.2x+8.6y=931.2. Using technology to solve this simultaneous equation yields; x= 60, y =72

For this case, we propose a system of two equations with two unknowns.

Let:

x: Represents the number of children's tickets

y: Represents the number of adult tickets

So, we clear x from the second equation:

x = 132-y

We replace in the first one.

72 adult tickets were sold.

60 tickets for children were sold

60 tickets for children

72 adult tickets

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

c

step-by-step explanation: