If y varies jointly as x and the cube of z and y=16 when x=4 and z=2 then y=0.5 when x=-8 and z=-3?

true or false?

F (False)

Step-by-step explanation:

 Jointly variation has the following form:

y=kxz

Where k is a constant of propotionality.

Substitute values:

If y=16, x=4 and z=2, then k is:

If x=-8 and z=-3 the the value of y is:

Then the answer is FALSE.

i got 86 for this

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