Two circles have the same center. circle p has a radius of p units. circle q has a radius of q units. which dilation could be used to prove that circles p and q are similar?

see attachment for choices. not sure if my answer is correct?

Option 1 is the correct option.

Step-by-step explanation:

Option 1. Since circle P has the radius p and circle Q with the radius q then dilation of Q will be measured by the ratio of p/q.

Since in the process of dilation ratio p/q should be > 1 therefore Option 1.

is the correct option.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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