Can someone !
if the length and width of a rectangle are each increased by ten percent, then the perimeter of the rectangle is increased by what percent?

The answer is 10%

Step-by-step explanation:

Let the length of the rectangle is x

Let the width of the rectangle is y

∵ They will increase by 10% each

∴ The new length = x × 110/100 = 1.1x

∴ The new width = y × 110/100 = 1.1y

∵ The old perimeter = 2(x + y) = (2x + 2y)

∴ The new perimeter = 2(1.1x + 1.1y) = 1.1(2x +2y)

∴ The new perimeter is greater than the old perimeter by 1.1 - 1 = 0.1

∴ The percentage of increasing in the perimeter = 0.1 × 100 = 10%

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3