Afield is a rectangle with a perimeter of
1140
feet. the length is
400
feet more than the width. find the width and length of the rectangular field.

Step-by-step explanation:

Let the length be represented by L. Then the width is L-400, and the perimeter is ...

  P = 2(L +W)

  1140 = 2(L +(L-400))

  570 = 2L -400 . . . . . . . divide by 2

  970 = 2L . . . . . . . . . . . . add 400

  485 = L . . . . . . . . . . . . . divide by 2

  L-400 = 485-400 = 85 . . . . . find the width

The length is 485 ft; the width is 85 ft.

2/3

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.