Suppose s=x1+x2+x3+x4s=x1+x2+x3+x4 where x1,x2,x3,x4x1,x2,x3,x4 are mutually independent and xixi has the bernoulli distribution with parameter pi=i5pi=i5 for 1≤i≤4.1≤i≤4.what is p{s=1}? p{s=1}? present your answer with four digits

The are mutually independent, so that

for any configuration of 0s and 1s .

We obtain when exactly one of the are 1, and the other three are 0. There 4 possible ways of obtaining such an outcome, and they are pairwise disjoint. So

Now,

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

the correct answer is x/3+10≥32

hope this !