What's the solution to x^2-11x+19=-5
(this is a quadratic equation)

8 and 3

Step-by-step explanation:

We first want to add 5 to both sides, making the equation x^2 -11x +24=0, now, we want to use the quadratic formula, which is( -b + sqrt(b^2 -4ac)) /2a  

for equations of the form ax^2 + bx +c, so in our case, a =1, b=  -11, and c=24,

when you plug in the variables, you will get the answers!   :)

x = 3 and x = 8 are the solutions

Step-by-step explanation:

Step 1:  Set the equation equal to zero

For this question, it is done by adding 5 to both sides

x² - 11x + 19 + 5 = -5 + 5

   x² - 11x + 24 = 0

Step 2:  Factor the equation

Think about what two numbers add up to -11 and multiply to 24...

they are -3 and -8, so those are our factors...

   (x - 3)(x - 8) = 0

Step 3:  Set each factor equal to zero and solve

x - 3 = 0,      so add three to both sides to isolate x

 x - 3 + 3 = 0 + 3

    x = 3

x - 8 = 0,      so add eight to both sides to isolate x

 x - 8 + 8 = 0 + 8

    x = 8

true

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: