An observer(o) spots a plane(p) taking off from a local airport and flying at a 29 degree angle horizontal to her line of sight and located directly above a tower(t). the observer also notices a bird circling directly above her. if the distance from the plane(p) to the tower(t) is 6,000ft., how far is the bird(b) from the plane(p).

Based on the diagram, we can say that the answer is 10824 feet. We know this when we apply the formula BP=OT because it is a rectangle. so we need to find OT using trigonometry using the formula  tan=OPP/ADJ like this

tan 29° = 6000 / x

x = 6000 / tan 29° = 10824

Step-by-step explanation:

I Hope this helps

Hence, the bird is 10824 feet away from the plane.

Step-by-step explanation:

Since we have given that

Angle of elevation = 29°

Length of plane to the tower = 6000 feet

So, it forms a right angled triangle.

So, we will use "Tangent":

Consider, ΔABC,

Hence, the bird is 10824 feet away from the plane.

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