Identify the vertex and the y-intercept of the graph of the function y=-2(x+2)^2+2

The vertex would be (-2, 2) and the y-intercept would be (0, -6)

Step-by-step explanation:

To find the vertex, we just use the base form of vertex form. In it, (h, k) is the vertex. So we can compare the two and figure out the vertex from that.

y = a(x - h)^2 + k

y = -2(x + 2)^2 + 2

This gives us a vertex of (-2, 2).

To find the y-intercept, put 0 in for x and solve for y.

y = -2(x + 2)^2 + 2

y = -2(0 + 2)^2 + 2

y = -2(2)^2 + 2

y = -2(4) + 2

y = -8 + 2

y = -6

step-by-step explanation:

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