What are the real zeroes of x^3+6x^2-9x-54

The answer is: 3,-3,-6

We need to find the values where the function tends to 0, so we need to make the equation, equal to 0:

Then, we have three factors multiplying each other, so we have to five three numbers which make at least one of those factors 0

So,

Trying with 3:

Trying with -3:

Trying with -6:

Have a nice day!

understand that i don't know the answers

will someone answer his question