Write the equation for the parabola that has x− intercepts (−2,0) and (1.2,0) and y− intercept (0,−4).

  y = (5/3)x^2 +(4/3)x -4

Step-by-step explanation:

Given the x-intercepts, you can write the quadratic as ...

  y = a(x +2)(x -1.2)

The y-intercept of this equation will be ...

  -4 = a(0 +2)(0 -1.2) = -2.4a

  -4/-2.4 = a = 5/3 . . . . divide by the coefficient of "a" and simplify

The equation is then ...

  y = (5/3)(x +2)(x -1.2) = (5/3)(x^2 +0.8x -2.4)

  y = (5/3)x^2 + (4/3)x - 4

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Verified by graphing.

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