Which values of k would cause this system of equations to have no solution? check all that apply.
6x + 4y = 14,
3x + 2y = k

x= -2y/3

-4y+4y=14

0y= 14

This has no solution.

Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

6(-2y/3)+4y=14

Expanding this we get: 6(-2y/3)+4y=14

-4y+4y=14

0y= 14

Thus, no solution.

450 is the final answer! : )

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.