What is the solution to the system of equations the equations 9x-10y=6, 8x-10y=-23, 9x+10y=-16, and 8x+10y=13

Answer to Q1:

(29,25.5)

Step-by-step explanation:

We have given a system of equations.

9x-10y = 6                        eq(1)

8x-10y = -23                     eq(2)

We have to solve given system of equations by finding the value of  x and y.

Subtracting eq(1) from eq(2), we have

9x-10y-(8x-10y) = 6-(-23)

9x-10y-8x+10y = 6+23

Adding like terms, we have

x+0y = 29

x = 29

Putting above value of x in eq(1), we have

9(29)-10y = 6

261-10y = 6

Adding -261 to both sides of above equation, we have

-261+261-10y = -261+6

-10y = -255

Dividing by -10 to both sides of above equation, we have

y = -255 / -10

y = 25.5

Hence, the answer of  9x-10y=6, 8x-10y=-23 is (29,25.5).

Answer to Q2:

(-29,24.5)

Step-by-step explanation:

We have given a system of equation.

9x+10y = -16                  eq(1)

8x+10y = 13                     eq(2)

We have to find the value of x and y.

Subtracting eq(1) from eq(2), we have

9x+10y-(8x+10y) = -16-13

9x+10y-8x-10y = -16-13

Adding like terms, we have

x +0y = -29

x = -29

Putting the value of x in eq(1), we have

9(-29)+10y = -16

-261+10y = -16

10y = -16+261

10y = 245

y = 245 / 10

y = 24.5

Hence , the solution of 9x+10y=-16, and 8x+10y=13 is (-29,24.5).

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb