Trignometry problem plz
no 3, 5 and 6

3. First factor as a difference of cubes:

For the remaining group, apply the double angle identity.

5. seems rather tricky. You might want to post another question for that problem alone...

6. Factorize the left side as a sum of cubes:

From here we have to prove that

We can write everything in terms of sine:

(double angle identity)

(angle sum identity)

After some simplifying, we're left with showing that

or

This last equality follows from what you could the triple angle identity for sine,

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?