Acash box contained $12.25 in quarters, dimes, and nickel. if there were five more than twice as many dimes as nickels and one less than three times as many quarters as nickels. how many of each kind of coin was there. explain ur answer

Step-by-step explanation:

Let n represent the number of nickels. Then the number of dimes is ...

  dimes = 5 + 2n

and the number of quarters is ...

  quarters = -1 + 3n

So, the total value of the cash in the box is ...

  0.05n + 0.10(5 +2n) + 0.25(-1 +3n) = 12.25

  1.00n + 0.25 = 12.25

  n = (12.25 -0.25)/1.00 = 12

  dimes = 5+2·12 = 29

  quarters = -1 +3·12 = 35

There are 12 nickels, 29 dimes, and 35 quarters.

Check

.05·12 +.10·29 +.25·35 = 0.60 +2.90 +8.75 = 12.25 . . . . answer checks OK

answer: what in the world is this

step-by-step explanation:

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you