Ineed with these maths questions urgent!

The first three terms of a different Fibonacci sequence are: a; b; a + b

Show that the 6th term of this sequence is 3a + 5b

4. (b) + (a + b) = a + 2b

5. (a + b) + (a + 2b) = 2a + 3b

6. (a + 2b) + (2a + 3b) = 3a + 5b

c) Given that the 3rd term is 7 and the 6th term is 29, find the value of a and the value of b.  

a + b = 7

3a + 5b = 29

II - 3*I

2b = 8 --> b = 4

a + 4 = 7 --> a = 3

Your answer to B is  8ab Your answer for C would be 36

Step-by-step explanation: If you have A+b you get Ab the you have 3A+5B that would be 8ab

If you have 7 and 29 and your trying to figure out B well its simple B would be 36 now i know that because look at the numbers you have 7 * 4 you get 28 then add 1 you got 29 so then you would due 7 * 5 you'd get 35 + 1 you get 36 so 36 is your answer.

207/8 is the right

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23