If one of two positive integers is 7 less than the other, and the product of the two integers is 78, find the integers.

Let the greater integer be x

Then other integer= x-7

A/q- x(x-7)= 78

=> x^2 -7x-78=0

=> x^2 -13x +6x -78=0

=> x (x-13) +6 (x-13)=0

=> (x-13)(x+6)= 0

So, x=13 or x= -6

since -6 is not a positive integer so the value of

x=13

other integer= x-7=13-7=6

Hence, the numbers are 13 and 6

HOPE IT IS USEFUL

21

jk it's 20

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1