Which function has the graph shown?

Option B. y = csc(x) + 1

Step-by-step explanation:

If we have to draw an asymptote graph( csc graph), we should draw the graph of sine first.

For y = a sin(bx+c) +d

Here from the given graph

a = (0+2)/2 = 1

period = (3π/2-π/2) = 2π

Therefore b = 2π/period = 2π/2π = 1

b = 1

Vertical shift d = 1

Now the equation will be y = 1×sin(1.x+0)+1

y = sinx + 1

Now we draw the sine graph y = sinx +1

Then we draw asymptotes touching the maximum and minimum values of sine graph.

Which reflects It's a graph of y = csc(x) + 1

Therefore option B. is the right answer.

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step-by-step explanation: