Find the area of the shaded sector. leave your answer in terms of π.

24π ft2

18π ft2

32π ft2

3π ft2

18π ft^2

Step-by-step explanation:

The area of the circle is

pi *r^2

pi * 12^2

144pi

The part that is shaded is 45 degrees

An entire circle is 360 degrees

The fraction that is shaded is 45/360 = 1/8

Multiply the area by the fraction that is shaded

1/8 * 144 pi

18 pi

18π ft2

Step-by-step explanation:

The circle has a radius of 12 ft and the angle of the sector is 45°.

Area of the sector (A) is given by the formula below:

Where is the angle of the sector and r is the radius of the circle

We know r = 12 and = 45°

Plugging these into the formula and simplifying, we get:

Thus, the area is sq. ft.

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9