Find three consecutive even integers that have a sum that is zero

-2, 0, +2

Step-by-step explanation:

Using one variable in different expression for each number, we can set up an equation equal to '0':

first integer: x

second integer: x + 2

third integer: x + 4

The sum of the integers is equal to '0':

x + x +2 + x + 4 = 0

Combine like terms: 3x + 6 = 0

Subtract 6 from both sides: 3x + 6 - 6 = 0 - 6 or 3x = -6

Divide by 3 on both sides: 3x/3 = -6/3

Solve for x = -2

second integer: x + 2 = -2 + 2 = 0

third integer: x + 4 = -2 + 4 = 2

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x