Jimmy made a trip to the ferry office and back. the trip there took two hours and the trip back took three hours. he averaged 20 mph faster on the trip there than on the return trip. find jimmy's average speed on the outbound trip.

60 mph

Step-by-step explanation:

We don't know how far Jimmy drives in each direction.  Let this distance be d.  Then, d = rate * time, and d = r(2 hours)  (where r represents his speed while driving to the ferry).

But it's also true that d = (r - 20 mph)(3 hours).

Equating d = r(2 hours)  and  d = (r - 20 mph)(3 hours), we get:

r(2) = (r - 20)(3), or 2r = 3r - 60.

Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.

Jimmy averaged 60 mph on the outbound trip.

false

step-by-step explanation:

i looked it up

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles