An exam has two probability problems, 1 and 2. if 37% of the students solved problem 1 and 12% of the students solved both problems 1 and 2, what percent of the students who solved problem 1 also solved problem 2?

  about 32%

Step-by-step explanation:

The desired probability is the conditional probability that problem 2 was solved given that problem 1 was solved. That is ...

  P(2|1) = P(1&2)/P(1) = 12%/37% ≈ .324 ≈ 32%

You can also think of it like this. If there were 100 students taking the exam, 37 solved the first problem. Of those 37, 12 solved the second one. 12 is about 32% of 37.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

step-by-step explanation:

options