Find all polar coordinates of point p = (6, 31°). explain steps and show work.

Solution:

P=(6, 31°)

P=(r , ∠ A)

r= Distance from origin to point P=6

∠A=31°, →Angle made by line with positive direction of x axis.

Now, polar coordinates is given by,

x= r cos A, and y= r sin A

x=6 cos 31°, y= 6 sin 31°

x= 6 × 0.915  and , y= 6 × 0.515

→ x= 5.490, and y=3.090  ⇒⇒Polar coordinates

-14 is the answer

hope this : ))

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2