You roll a number cube twice. what is the probability of rolling a 2 first and then rolling an odd number? 1/36,1/12,1/9,1/4

option B is correct, i.e. 1/12.

Step-by-step explanation:

You roll a number cube twice.

the probability of rolling a "2" first is P(A) = 1/6.

And then rolling an "odd number" is P(B) = 3/6.

Since two events are independent of each other, we can use following rule:-

P(A and B) = P(A)*P(B)

Combined probability of two events is:-

P(A and B) = (1/6)*(3/6) = 3/36 = 1/12.

Hence, option B is correct, i.e. 1/12.

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question